Given the function f(x) = 1/(sqrt x)

a. Does f(x) exist at x=0?
b. Does f'(x) exist at x=0?
c. Explain why integral (from 0->1) f(x)dx does exist.

THANK YOU.

3 answers

a) no, one is not allowed to have zero in the denominator.
b. f(x)=1/sqrt(x)
f'= -1/(2 x-3/2) yes it exists

c. if an endpoint does not exist, one cannot integrate it.
Thank you so much! but are you sure for part c.?
so idk the answer
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