The given function is defined for all

Question

x > 0 except at
x = 8.
Find the value that should be assigned to f(8), if any, to guarantee that f will be continuous at 8. (If an answer does not exist, enter DNE.)

f(x)= Sqrt( x^2-64/x-8)

Answer 1

limit √( (x^2 - 64)/(x-8)) as x -->8
= lim √( (x-8)x+8)/(x-8) , as x ---> 8
= lim √(x+8) , as x---> 8
= √16
= 4