limit √( (x^2 - 64)/(x-8)) as x -->8
= lim √( (x-8)x+8)/(x-8) , as x ---> 8
= lim √(x+8) , as x---> 8
= √16
= 4
The given function is defined for all
x > 0 except at
x = 8.
Find the value that should be assigned to f(8), if any, to guarantee that f will be continuous at 8. (If an answer does not exist, enter DNE.)
f(x)= Sqrt( x^2-64/x-8)
1 answer