no, since when x < 0, sqrt(x) is not defined. so, neither is sqrt(5-sqrt(x))
the domain is just [0,25]
find the domain of the real valued function;
f(x) = sqrt(5 - (sqrtx))
my solution:
5 - (sqrt x) >=0
-(sqrt x) >= -5
(sqrt x) <= 5
x <= 25
(-infinity, 25]
is this correct?
2 answers
thank you very much!