Given the equation:

Question

6CO2(g) + 6H2O(l) -> C6H12O6(s) + 6O2(g)

What is the minimum number of liters of CO2(g), measured at STP, needed to produce 32.0 grams of oxygen?

1) 264 L
2) 32.0 L
3) 192 L
4) 22.4 L

How do I solve?

Answer 1

32.0 g O2 = 1 mole O2
1 mole O2 = 22.4 L
The mole ratio shown by the coefficients in the chemical equation is the same as the volume (liters) ratio. So,
6 L of CO2 produce 6 L O2, or
1 L CO2 make 1 L O2
How many liters CO2 would produce 22.4 L O2 ??

Answer 2

22.4