To determine which equation best represents the conservation of matter, we need to ensure that the number of atoms for each element is the same on both sides of the equation.
Let's analyze each equation:
A: 3H₂O + 3CO₂ → C₆H₁₂O₆ + 6O₂
- Reactants: 3H₂O (3 H, 3 O) + 3CO₂ (3 C, 6 O) = 6 C, 6 H, 9 O
- Products: C₆H₁₂O₆ (6 C, 12 H, 6 O) + 6O₂ (0 C, 0 H, 12 O) = 6 C, 12 H, 18 O
- Not balanced.
B: 6H₂O + 10CO₂ → C₆H₁₂O₆ + 4O₂
- Reactants: 6H₂O (12 H, 6 O) + 10CO₂ (10 C, 20 O) = 10 C, 12 H, 26 O
- Products: C₆H₁₂O₆ (6 C, 12 H, 6 O) + 4O₂ (0 C, 0 H, 8 O) = 6 C, 12 H, 14 O
- Not balanced.
C: 6H₂O + 6CO₂ → C₆H₁₂O₆ + 6O₂
- Reactants: 6H₂O (12 H, 6 O) + 6CO₂ (6 C, 12 O) = 6 C, 12 H, 18 O
- Products: C₆H₁₂O₆ (6 C, 12 H, 6 O) + 6O₂ (0 C, 0 H, 12 O) = 6 C, 12 H, 18 O
- Balanced.
D: 6H₂O + 6CO₂ → C₃H₁₂O₃ + 3O₂
- Reactants: 6H₂O (12 H, 6 O) + 6CO₂ (6 C, 12 O) = 6 C, 12 H, 18 O
- Products: C₃H₁₂O₃ (3 C, 12 H, 3 O) + 3O₂ (0 C, 0 H, 6 O) = 3 C, 12 H, 9 O
- Not balanced.
The only equation that maintains the same amount of each atom on both sides is C. Therefore, the answer is:
C 6H₂O + 6CO₂ → C₆H₁₂O₆ + 6O₂
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