Given that x^2-6x+3k=0 has 2 real number roots, a and B, with opposite signs (one root is positive and the other root is negative) determine the range of values of k.
2 answers
no
x^2 - 6x = 0 has two roots of 0 and 6
looking at the graph of y = x^2 - 6x , if I drop the graph I will get 2 roots, one positive and the other negative.
e.g. x^2 - 6x - 16 = 0 will have roots of -2 and 8
so in x^2 - 6x + 3k = 0
3k < 0
k < 0
check by graphing in a webpage like
www.desmos.com/calculator
looking at the graph of y = x^2 - 6x , if I drop the graph I will get 2 roots, one positive and the other negative.
e.g. x^2 - 6x - 16 = 0 will have roots of -2 and 8
so in x^2 - 6x + 3k = 0
3k < 0
k < 0
check by graphing in a webpage like
www.desmos.com/calculator