Which describes the number and type of roots of the equation x^2 -625=0?

Yes. A quadratic has two roots. In this case both are real. If one were complex, the other would be too. (The complex conjugate)

No, that is not correct. To find the roots of the equation x^2 - 625 = 0, you can first take the square root of both sides:

x^2 = 625
√(x^2) = √(625)

This gives you two possible equations:

x = 25
x = -25

So, the correct answer is C. There are 2 real roots.

To determine the number and type of roots for the equation x^2 - 625 = 0, you can use the factoring technique.

First, rewrite the equation as x^2 = 625.

Then, take the square root of both sides of the equation.

√(x^2) = ±√(625)

This gives you two separate equations:

x = ± 25

So, the solutions for x are 25 and -25.

Therefore, the correct answer is indeed C. 2 real roots.