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Given that the graph of f(x) passes through the point ( 9, 7 ) and that the slope of its tangent line at (x,f(x)) is 3 x + 5, what is f( 2 )?

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f ' (x) = 3x+5
f(x) = (3/2)x^2 + 5x + c
but (9,7) lies on it, so
7 = (3/2)(81) + 5(9) + c
c = -319/2

f(x) = (3/2)x^2 + 5x - 319/2
f(2) = (3/2)(4) + 5(2) - 319/2
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