Given f(x)=3x^2+4, evaluate each of the following:

Question

a.) f(x+2)
b.) f(x+8)-f(x)/h, h doesn’t =0

Answer 1

f(x)=3x^2+4
f(x+2) = 3(x+2)^2 + 4
= 3(x^2 + 4x + 4) + 4
= 3x^2 + 12x + 12 + 4
= 3x^2 + 12x + 16

f(x+h)-f(x)/h <----- I am sure you have a typo and you meant h instead of 8, since I know where this is leading to
= ( (3(x+h)^2 + 4 - (3x^2 + 4) )/h
= (3x^2 + 6xh + 3h^2 + 4 - 3x^2 - 4)/h
= (6xh + 3h^2)/h
= 6x + 3h , h ≠ 0
=

Answer 2

Thank you does that mean the final answer for part b is 6x+3h?

Answer 3

Yes, it is 6x + 3h
in your next section of your topic you will find the word "limit" in front of
each expression of the solution, I bet you can't wait to get there.