Asked by Laura
give an example to show that a^2 congruent to b^2 mod n need not imply that a congruent to b mod n.
Answers
Answered by
Count Iblis
I think you mean that a does not have to be congruent to plus or minus b, otherwise the problem is rather trivial.
You can construct an example as follows. If, Mod n, we have
a^2 = b^2
then that means that:
(a-b)(a+b) = 0
This then does not mean that one of the two factors must be zero as it is possible that a-b and a + b have divisors in common with n, such that upon multiplication, you get a multiple of n making it zero Mod n.
If n = 100, then we have, e.g.:
10*20 = 0 -------->
(15 - 5)*(15 + 5) = 0 ---->
15^2 = 5^2
Yet modulo 100, 15 is not 5 nor is it
-5.
You can construct an example as follows. If, Mod n, we have
a^2 = b^2
then that means that:
(a-b)(a+b) = 0
This then does not mean that one of the two factors must be zero as it is possible that a-b and a + b have divisors in common with n, such that upon multiplication, you get a multiple of n making it zero Mod n.
If n = 100, then we have, e.g.:
10*20 = 0 -------->
(15 - 5)*(15 + 5) = 0 ---->
15^2 = 5^2
Yet modulo 100, 15 is not 5 nor is it
-5.
Answered by
James
I don't get it
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