From a building EF, the angles of depression to the top and bottom of a tree are 41° and 62° respectively. The tree is 15m from the building. (1)Draw diagram to show and (2) determine the height of the tree.

Answer 1

I assume you sketched the diagram
From the point of observation, draw a horizontal to the tree, that distance will be 15 metres.
You now have two right-angled triangles.
let the height of the tree be made up of h1 and h2
tan62° = h1/15 , h1 = 15tan62

similarly find h2

Your tree will have a height of
h1 + h2
= ....

Answer 2

Tan41 = h2/15.
h2 = 13 m.

Tan62 = (h1+h2)/15
h1+h2 = 28 m.
h1+13 = 28,
h1 = 15 m. = Ht. of tree.