A man is standing in the corridor of a ten storey building and looking at a tall tree in front of the building he sees the top of the tree at an angle of depression 30degree if the tree is 200metre tall and the man's eyes are 300metre above the ground calculate the angle of depression of the foot of the tree as seen by the man

Answer 1

tan30=500/x
1/root3

Answer 2

since the top of the tree is 100m down, and tan30° = 1/√3,
the tree is 100√3 meters from the building.

So if the angle to the foot of the tree is x, then
tanx = 300 / 100√3 = 3/√3 = √3
x = 60°