force in the x-direction with magnitude Fx=18N-(0.530N/m)x is applied to a 5.50 box that is sitting on the horizontal, frictionless surface of a frozen lake. is the only horizontal force on the box.

Question

force in the x-direction with magnitude Fx=18N-(0.530N/m)x is applied to a 5.50 box that is sitting on the horizontal, frictionless surface of a frozen lake.  is the only horizontal force on the box.
what is the speed after 12m. starting from rest and x=0

Elena · Answer

F=18-0.53•x a=F/m=(18-0.53•x)/5.5 v=sqrt(2•a•x)=sqrt[(18-0.53•x)x/5.5]= = sqrt[(18 - 0.53•12) •12/5.5=5.04 m/s

n8 · Answer

the first answer is wrong

Alex · Answer

Integral of F(x) = .5mv^2 18x-.5(.53)x^2=.5mv^2 find v.

Mirian · Answer

8.04m/s