Mirian

This page lists questions and answers that were posted by visitors named Mirian.

Questions

The following questions were asked by visitors named Mirian.

Answers

The following answers were posted by visitors named Mirian.

Take the integral of F(x) which is 18.0x-.5(.530)x^2 then plug in 14.0 for x =200.06J so .5mv^2=W since v(initial) is zero so then solve for v v(final)=((2*200.06)/6)^(1/2) v(final)=8.17m/s

Take the integral of F(x) which is 18.0x-.5(.530)x^2 then plug in 12.0 for x =177.84J so .5mv^2=W since v(initial) is zero so then solve for v v(final)=((2*177.84)/8.7)^(1/2) v(final)=6.39m/s

work to lift = m g h = 850 * 9.81 * 14.8 =123409.8 J/min work for Ke = (1/2)(850)(17.7)^2 =133148.25J/min C) add those and divide by 60 to get Joules/second or Watts =(123409.8+133148.25)/60=4276 J/sec or W

a) W=2.4*1.5*cos(0)= 3.6J b) W=0.600*1.5*cos(180)= -0.9J c) W=0J because the displacement and the normal force is perpendicular to each other so cos(90)=0 d) W=0J for the same reason as part (c), but with the gravity e) W(net)= 3.6+(-0.9)+0+0= 2.7J you ar...