Asked by YASER
A pump is required to lift a mass of 850 of water per minute from a well of depth 14.8 and eject it with a speed of 17.7 .
Part A
How much work is done per minute in lifting the water?
Part B
How much in giving the water the kinetic energy it has when ejected?
Part C
What must be the power output of the pump?
Part A
How much work is done per minute in lifting the water?
Part B
How much in giving the water the kinetic energy it has when ejected?
Part C
What must be the power output of the pump?
Answers
Answered by
drwls
Your numbers require dimensions.
Answered by
Hehehe
Thulu
Answered by
Mirian
work to lift = m g h = 850 * 9.81 * 14.8 =123409.8 J/min
work for Ke = (1/2)(850)(17.7)^2 =133148.25J/min
C) add those and divide by 60 to get Joules/second or Watts
=(123409.8+133148.25)/60=4276 J/sec or W
work for Ke = (1/2)(850)(17.7)^2 =133148.25J/min
C) add those and divide by 60 to get Joules/second or Watts
=(123409.8+133148.25)/60=4276 J/sec or W
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.