work=integral f(x)*dx over limits 0 to 14
= INt (18-.530x)dx= 18x-.265x^2 over limits
= 18(14)-.265(14^2)= you do it.
then what work is put into kinetic energy, so set the above equal to 1/2 m v^2, and solve for v.
In my head, I get about 7.4 m/s. Check that.
A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 7.40 kg box that is sitting on the horizontal, frictionless surface of a frozen lake. F(x) is the only horizontal force on the box.If the box is initially at rest at x=0, what is its speed after it has traveled 14.0 m ?
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