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For the following chemical reaction, how many moles of lead(ii)iodide (PbI2) will be produced from 8 mol of potassium iodide (KI)?

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I don't see a chemical reaction so I'll assume one.
2KI + Pb^2+ ==> PbI2 + 2K^+.
8 mols KI x (1 mol PbI2/2 mols KI) = 8 x 1/2 = ?

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