For the following acids:

Question

i. CH3COOH
ii. HNO2
iii. HCN
a) What is the dissociation equation in an aqueous solution?
b)Give the KA expression for each of the acids.
c)Identify the acid-base pairs.

Answer 1

a)CH3COOH + H2O ==> CH3COO^- + H3O^+
b) Ka = (H3O^+)(CH3COO^-)/(CH3COOH)
c) CH3COOH is the acid/CH3COO^- is the base. H2O is the base/H3O^+ is the acid.
The others are done the same way. Just remember the definition of a Bronsted-Lowry acid/base and you can't go wrong.