I wrote the dissociation or ionization in water for each of the following acids. I just want someone to check if they are right.
a) HC3H5O2(aq)<===> H^+(aq)+ C3H5O2^-(aq)
b) (CH3)2NH2^+(aq)<===> H^+(aq)+ (CH3)2NH(aq)
c) CH3COOH(aq)<===> H^+(aq)+ CH2COOH^-(aq)
d) H2PO4^-(aq)<===> H^+(aq)+ HPO4^2-
e) [Mn(H2O)6]^2+ <===> I don't know what to do with this one
Thanks
3 answers
e) [Mn(H2O)6]^2+(aq)<===> H^+(aq)+ [Mn(H2O)5]5OH^+(aq)
a) HC3H5O2(aq)<===> H^+(aq)+ C3H5O2^-(aq)
This is an odd way to write the this
a) C3H5O2H(aq)<===> H^+(aq)+ C3H5O2^-(aq)
Your answer to a) means you have shown the wrong proton dissociating here.
c) CH3COOH(aq)<===> H^+(aq)+ CH2COOH^-(aq)
should be
c) CH3COOH(aq)<===> H^+(aq)+ CH3COO^-(aq)
[It is possible to remove the proton that you have shown but not in water]
I am not clear what they are after for e) either.
They may be simple be looking for
e) [Mn(H2O)6]^2+H2O<===> H^+(aq)+ [Mn(H2O)6]OH^+(aq)
This is an odd way to write the this
a) C3H5O2H(aq)<===> H^+(aq)+ C3H5O2^-(aq)
Your answer to a) means you have shown the wrong proton dissociating here.
c) CH3COOH(aq)<===> H^+(aq)+ CH2COOH^-(aq)
should be
c) CH3COOH(aq)<===> H^+(aq)+ CH3COO^-(aq)
[It is possible to remove the proton that you have shown but not in water]
I am not clear what they are after for e) either.
They may be simple be looking for
e) [Mn(H2O)6]^2+H2O<===> H^+(aq)+ [Mn(H2O)6]OH^+(aq)
Thanks, that helped a lot