Find the x-intercepts (if any) for the graph of the quadratic function. 6x2 +12x+5=0
Give your answers in exact form. Show your work.
5 answers
by precalc you should surely know how to find the roots of a quadratic. What did you get?
6x2 ?
ever hear of the quadratic formula?
x = (-12±√(144-120))/(2*6)
x = (-12±√(144-120))/(2*6)
B^2-4AC=
144-120= 24
x=12+sqrt24 / 12
2*2*2*3
sqrt24=sqrt2*2*2*3= + 2* sqrt6
x=(12+2*2.449)/12
x =(12+√24)/12=1+1/6√ 6 = 1.408
144-120= 24
x=12+sqrt24 / 12
2*2*2*3
sqrt24=sqrt2*2*2*3= + 2* sqrt6
x=(12+2*2.449)/12
x =(12+√24)/12=1+1/6√ 6 = 1.408
you are correct about
x = (12+√24)/12
There is also
x = (12-√24)/12
x = (12+√24)/12
There is also
x = (12-√24)/12
1 answer