To find the x-intercept, set y=0 and solve for x
To find the y-intercept, set x=0 and solve for y
the domain of a standard parabola that opens either up or down is
x "is an element of" R
the domain is either y ≥ "the y value of the vertex", if it opens up or
y ≤ "the y value of the vertex" if it opens downwards
Please explain to me how to do the following problems, I don't understand them. Thanks!
Find the x-intercepts (if any) for the graph of the quadratic function.
1.f(x) = (x + 2)2 - 4
Find the y-intercept for the graph of the quadratic function.
5.y + 9 = (x + 3)2
Find the domain and range of the quadratic function whose graph is described.
7.The vertex is (1, -15) and the graph opens up.
1 answer
4 answers