To analyze the quadratic function \( f(x) = (x+2)^2 - 9 \), we will identify the vertex, intercepts, axis of symmetry, domain, and range.
Step 1: Identify the Vertex
The function is in vertex form \( f(x) = a(x-h)^2 + k \), where the vertex is at the point \( (h, k) \).
For \( f(x) = (x+2)^2 - 9 \):
- \( h = -2 \)
- \( k = -9 \)
Thus, the vertex is at the point \( (-2, -9) \).
Step 2: Find the x-intercepts
To find the x-intercepts, set \( f(x) = 0 \): \[ 0 = (x+2)^2 - 9 \] Adding 9 to both sides: \[ 9 = (x+2)^2 \] Taking the square root of both sides: \[ \sqrt{9} = x + 2 \quad \text{or} \quad -\sqrt{9} = x + 2 \] This gives us two equations:
- \( x + 2 = 3 \) → \( x = 1 \)
- \( x + 2 = -3 \) → \( x = -5 \)
Thus, the x-intercepts are \( (1, 0) \) and \( (-5, 0) \).
Step 3: Find the y-intercept
To find the y-intercept, set \( x = 0 \): \[ f(0) = (0 + 2)^2 - 9 = 4 - 9 = -5 \] So, the y-intercept is \( (0, -5) \).
Step 4: Determine the Axis of Symmetry
The axis of symmetry is a vertical line that passes through the vertex. The equation of the axis of symmetry is given by \( x = h \): \[ \text{Axis of symmetry: } x = -2 \]
Step 5: Determine the Domain
The domain of a quadratic function is all real numbers: \[ \text{Domain: } (-\infty, \infty) \]
Step 6: Determine the Range
The range of the function is determined by the vertex. The vertex \( (-2, -9) \) is the lowest point of the parabola, and since it opens upwards, the range is: \[ \text{Range: } [-9, \infty) \]
Summary of Results
- The vertex of the parabola is \((-2, -9)\).
- The x-intercepts are \((1, 0)\) and \((-5, 0)\).
- The y-intercept is \((0, -5)\).
- The axis of symmetry is \( x = -2 \).
- The domain is \( (-\infty, \infty) \).
- The range is \( [-9, \infty) \).
Final Answers
- The axis of symmetry is: \( x = -2 \)
- The domain is: \( (-\infty, \infty) \)
- The range is: \( [-9, \infty) \)