Find the voltage across each resistor in a series circuit. Note: R is the lowest value and all others are multiples of that value as indicated.

Question

(there is no diagram for this circuit)

double battery cell = 15v
resistor1 = R
resistor2 = 2R
resistor3 = 4R

my answer is
1r+2r+4r=7r
15v(r/7r)
15v(2r/7r)
15v(4r/7r)

Answer 1

I = E/(R+2R+4R) = 15/7R = Current through each resistor.
V1 = I*R1 = 15/7R * R = 15/7 volts.
V2 = I*R2 = 15/7R * 2R = 30/7 volts.
V3 = I*R3 =15/7R * 4R = 60/7 volts.

Check: V1 + V2 + V3 = 15/7 + 30/7 + 60/7 = 105/7 = 15 volts.