Asked by mike
At what voltage would a 9 μF capacitor have the energy to lift 3 grams by 1 cm?
i understand i need the0.5CV^2 equation however I don't know how to answer this
i understand i need the0.5CV^2 equation however I don't know how to answer this
Answers
Answered by
Damon
so how many Joules do you need?
potential energy = m g h
= 3 *10^-3 *9.81* 10^-2 = .5*9*10^-6 V^2
30*9.81 = .5*9 V^2
potential energy = m g h
= 3 *10^-3 *9.81* 10^-2 = .5*9*10^-6 V^2
30*9.81 = .5*9 V^2
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