F(x) = X^2 -4X -3.
V(h , k),
h = Xv = -b/2a = 4/2 = 2,
k = Yv = F(2) = 2^2 -4*2 -3 = -7,
V(2 , -7).
Line of sym.: X = h = 2.
F(2) = -7 = min. (Eq opens upward)
Find the vertex, the line of symmetry, the maximum or minimum of the quadratic function, and graph the function.
f(x)=x^2-4x-3
What is the vertex? (Type an ordered pair)
What is the equation of the line of symmetry?
x=
What is the maximum/minimum of f(x)?
Is the value, f(2)= -7 a minimum or maximum?
1 answer
0 answers