find the vertex, the line of symmetry and the maximum or minimum value of f(x). graph the function. f(x)=-(x+6)^2-2
The vertex is The line of symmetry is x=
The minimum/maximum value of f(x) is?
The value of f(-6) =-2 is maximum or minimum?
and the graph goes up or down.
Thank you
5 answers
and your thinking is? I will be happy to critique your thinking. It will do you little lasting good if I do these for you.
I believe that x=-2 and the maximum is -2 and the graph goes downward. I did do some excerises with my school work but haven't mastered this.
pls let me know if I have anything right. I appericate you pushing me to find the answer.
pls let me know if I have anything right. I appericate you pushing me to find the answer.
"I believe that x=-2 and the maximum is -2 and the graph goes downward...."
How did you find the maximum of f(x)?
Try a tabulation of f(x) from -10 to 0 and see if you spot the maximum at -2 or elsewhere.
You will find that the function was expressed in the form for a reason:
f(x) = A(x-k)² + B
How did you find the maximum of f(x)?
Try a tabulation of f(x) from -10 to 0 and see if you spot the maximum at -2 or elsewhere.
You will find that the function was expressed in the form for a reason:
f(x) = A(x-k)² + B
ok the vertex is (-6,2) the line of symmetry is x=-6 and the vlue is max at 2, the graph goes downward. can someone please tell me if I am right. I am trying here.
Could you please verify from your tabulation the value of f(x) when x = -6 (i.e. at the vertex)?
Otherwise the rest are correct.
Otherwise the rest are correct.
1 answer