Find the vertex of the parabola y=3x^2+x+5
which method did they teach you?
Completing the square or using a formula?
y=3x^2+x+5= 3(x^2 + x/3 + ? ) + 5
= 3(x^2 + x/3 + 1/36 ) + 5 -1/36
= 3(x+ 1/6)^2 + 4 35/36
vertex at x=-1/6
which method did they teach you?
Completing the square or using a formula?
y=3x^2+x+5= 3(x^2 + x/3 + ? ) + 5
= 3(x^2 + x/3 + 1/36 ) + 5 -1/36
= 3(x+ 1/6)^2 + 4 35/36
vertex at x=-1/6
3 answers
1 answer
1 answer
1 answer