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Find the vertex of the parabola given by f(x) = x^2 - 3x + 4

My answer was (3,13). Am I correct?

1 answer

f(x)=x^2-3x+9/4 + 4-9/4
= (x-3/2)^2 + 7/4

looks like the vertex is at x=3/2, y= you compute it.

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