To find the second term, we plug in n=2 into the formula for A(n):
A(2) = 3 + (2 - 1)(4)
A(2) = 3 + 1(4)
A(2) = 3 + 4
A(2) = 7
So the second term is 7.
To find the fourth term, we plug in n=4 into the formula for A(n):
A(4) = 3 + (4 - 1)(4)
A(4) = 3 + 3(4)
A(4) = 3 + 12
A(4) = 15
So the fourth term is 15.
To find the tenth term, we plug in n=10 into the formula for A(n):
A(10) = 3 + (10 - 1)(4)
A(10) = 3 + 9(4)
A(10) = 3 + 36
A(10) = 39
So the tenth term is 39.
Find the second, fourth, and tenth terms of the sequence described by the rule.
A(n) = 3 + (n - 1)(4); A(2) = (Simplify your answer. Type an integer or a decimal .)
1 answer