Asked by ellie
Find the second, fourth, and tenth terms of the sequence described the the rule.
A(n)=4+(n-1)(8)
A(n)=4+(n-1)(8)
Answers
Answered by
Steve
huh? Just plug in the numbers for n:
A(2) = 4+(2-1)(8) = 4+1*8 = 4+8 = 12
and similarly for any other values of n.
A(2) = 4+(2-1)(8) = 4+1*8 = 4+8 = 12
and similarly for any other values of n.
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