Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=-2+(n-1)(-2.2)

Answer 1

A(n)=-2+(n-1)(-2.2)
= -2 - 2.2n + 2.2
= .2 - 2.2n

since term numbers are labeled with whole numbers, n ≥ 1
and the first term is -2
and the common difference is -2.2

the fourth term = a + 3d = -2 + 3(-2.2) = -8.6
then tenth term = .....

Answer 2

what, you can't plug in values?

A(1) = -2+(1-1)(-2.2) = -2
A(2) = -2+(2-1)(-2.2)
and so on

hint. Just keep subtracting 2.2 to get the next term.

Answer 3

3.
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

A(n) = –3 + (n – 1)(–2.2)


–2.2, –11.8, –19.8


–3, –9.6, –22.8


–3, –11.8, –25


0, –6.6, –19.8

The answer is either letter A, letter B, or letter C