To solve the equation \( n^3 = 64 \), we first need to find the cube root of 64.
Calculating the cube root: \[ n = \sqrt[3]{64} \]
We also know that: \[ 64 = 4^3 \]
Thus, we find that: \[ n = \sqrt[3]{64} = 4 \]
Now, we check if there are any other possible values for \( n \). The equation \( n^3 = 64 \) also implies that the only real cube root of a positive number is positive. Therefore: \[ n = -\sqrt[3]{64} \] is not a valid solution since it results in \( (-4)^3 = -64 \).
Next, evaluating the choices:
- Choice A: \( n = \sqrt[3]{64} \) is true, since \( \sqrt[3]{64} = 4 \).
- Choice B: \( n = -\sqrt[3]{64} \) is false, since the cube of \( -4 \) does not equal \( 64 \).
- Choice C: \( n = 4 \) is true, as we found this to be the solution.
- Choice D: \( n = -4 \) is false, since \( (-4)^3 = -64 \), which does not satisfy the equation.
- Choice E: This choice is also false because we have valid solutions with choices A and C.
Thus, the correct choices are:
- Choice A: \( n = \sqrt[3]{64} \)
- Choice C: \( n = 4 \)
So the answers are A and C.