Asked by sue
2x^=5-2x find the real solution using the quadratic formula
Answers
Answered by
Steve
first rearrange the terms so you have
2x^2 + 2x - 5 = 0
Now just plug in the formula, where
a = 2
b = 2
c = -5
x = (-2±√(2^2 + 4*2*5))/(2*2)
= (-2±√44)/4
= (-1±√11)/2
2x^2 + 2x - 5 = 0
Now just plug in the formula, where
a = 2
b = 2
c = -5
x = (-2±√(2^2 + 4*2*5))/(2*2)
= (-2±√44)/4
= (-1±√11)/2
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