Asked by Daisy
Find all real solution of the equation sin^2x = -2+2cosx
Answers
Answered by
Steve
since sin^2 = 1-cos^2,
1-cos^2 = -2 + 2cos
cos^2 + 2cos - 3 = 0
(cos+3)(cos-1) = 0
cos=1, so x = 0,2pi,4pi,...
why not -3?
1-cos^2 = -2 + 2cos
cos^2 + 2cos - 3 = 0
(cos+3)(cos-1) = 0
cos=1, so x = 0,2pi,4pi,...
why not -3?
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