Find the range of a projectile launched at an angle of 45 with an intial velocity of 25 m/s .

Answer 1

R = v^2/g

Answer 2

45 25m/s

Answer 3

I find answer

Answer 4

Zenda

Answer 5

Find answer

Answer 6

Studying

Answer 7

Angle 45degree and velocity 25 m/what is range

Answer 8

Range=(initial velocity)^2 times sin(2teta)/g. =(25m/s)^2 x sin(90)/9.81 =63.7meter