the verical velocity component at 30 degrees is 1/2 the vertical component if straight up (after all, what is the sine 30 degrees?)
so if vertical velocity is doubled, then energy is quadrupled, so potential energy at the top is four times, so height must be 4x, or 200m. Of course, if the ball is thrown straight up, the horizonal range is ...zero...
a ball is thrown at a vertical velocity to an angle of 30 degree above the horizontal and rises to a maximum height of 50 meters.if the angle is tripled find the maximum height and the horizontal range of a projectile for the same intial velocity
1 answer
1 answer