using T for theta
dR/dT = (Vo^2 /9.81) cos2T
(note max range when T = 45 degrees :) )
100 dT/T = 2
dT = .02 T = .02 * pi/6
dR = (Vo^2 /9.81) cos2T dT
100 dR/R = cos 2T dT / sin 2T
Any help on how to solve this?
The range of a projectile launched at an angle θ from the ground with velocity v0 is given by R(θ) = [v0^2 sin 2(θ)]/9.81 . If the projectile is launched at an angle of θ = π/6, use differentials to approximate the percentage change in the range of the
projectile if the angle was increased by 2%.
1 answer
1 answer