I was wondering if you could help me solve this projectile motion problem.

A projectile is launched with an initial speed of 14.5 m/s at an angle of 35° above the horizontal. The object lands at the same height from which it was launched. Air resistance is negligible. Determine

a) Maximum height: 3.5m

b) The projectiles horizontal displacement when it hits the ground

c) How long it will take to reach the maximum height. 0.85s

I've done everything except b. The problem is that you're only given the time and velocity after. I tried d=vt and that gave me a wrong answer. Am I leaving something out?

Problem is the textbook gives me the formula: ΔDx=vi^2/g * Sin2(θ), which works however we did not learn the material that way.

1 answer

you can see how that formula was achieved if you read the article on trajectory in wikipedia.

Maybe your textbook also explains how the formula was derived. In any case, just use it to get your answer!