Find the missing value to make the point (2, __) on the equation y=9x

Question

2
+ 2.

Answer 1

To find the missing value in the point \((2, __)\) on the equation \(y = 9x^2 + 2\), we need to substitute \(x = 2\) into the equation.

Let's do that step by step:

1. Substitute \(x = 2\) into the equation: \[ y = 9(2^2) + 2 \]

2. Calculate \(2^2\): \[ 2^2 = 4 \]

3. Multiply by 9: \[ 9 \times 4 = 36 \]

4. Add 2: \[ 36 + 2 = 38 \]

So, when \(x = 2\), \(y = 38\).

Therefore, the missing value is \(38\), making the point \((2, 38)\).