Asked by Greg powell
Write missing monomials to make an identity: A) (.....+2a)^2=.....+12ab+4*.... B) (3x+.....)^2=....*x^2+.....+49y^2
Answers
Answered by
oobleck
12 = 2(2*3) so (3b+2a)^2 = 9b^2 + 12ab + 4a^2
now you try the other. note that (3x)^2 = 9x^2 and (7y)^2 = 49y^2
now you try the other. note that (3x)^2 = 9x^2 and (7y)^2 = 49y^2
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