Find the linearization L(x) of the function at a.

Question

f(x) = x^4/5, a = 32

Answer 1

Assuming you mean x^(4/5), else x^4 is huge at x=32,

f(32) = 16
f' = 4/5 x^(-1/5)
f'(32) = 4/5 * 1/2 = 2/5

So, now you have a point (32,16) and a slope (2/5). What's the line?