impatient much?
still can't type fractions?
find the linearization L(x) of the function a. f(x)=sin(x), a=pi,3
2 answers
Consider the function used to find the linearization at a.
L(x) = f(a) + f'(a) (x-a)
Substitute the value of a=π/3 into the linearization function.
L(x) = f(π/3) + f'(π/3) (x-π/3)
Evaluate f(π/3) which is √3/2
Find the derivative and evaluate it at a = π/3 which is 1/2
Substitute the components into the linearization function in order to find the linearization at a.
L(x) = √3/2 + 1/2 (x- √3/2)
Simplify each term.
L(x) = √3/2 + x/2 - π/6
L(x) = f(a) + f'(a) (x-a)
Substitute the value of a=π/3 into the linearization function.
L(x) = f(π/3) + f'(π/3) (x-π/3)
Evaluate f(π/3) which is √3/2
Find the derivative and evaluate it at a = π/3 which is 1/2
Substitute the components into the linearization function in order to find the linearization at a.
L(x) = √3/2 + 1/2 (x- √3/2)
Simplify each term.
L(x) = √3/2 + x/2 - π/6
1 answer