y = 2x^2 - 3
inverse:
x = 2y^2 - 3
2y^2 = x+3
y^2 = (x+3)/2
y = ± √( (x+3)/2 )
btw, the inverse is not a function
Find the inverse of the function
f(X)= 2x^2 - 3
3 answers
since f is not single-valued, it has no inverse.
For x>=0,
f^-1(x) = √((x+3)/2)
There is also a branch for x <= 0
For x>=0,
f^-1(x) = √((x+3)/2)
There is also a branch for x <= 0
sorry. The branches split at x = -3, not x=0.