x = -y^2 + 16
-y^2 = x-16
y^2 = -x + 16
y = sqrt (-x+16), x </= 16
do you mean
(5/x)-3
or
5/(x-3) ???
Find the inverse of the function:
f(x)=-x²+16, x≥0
f(x)=5/x-3
3 answers
5/(x-3)
y = 5/(x-3)
x = 5/(y-3)
y x - 3 x = 5
y x = 3 x + 5
y = 3 + (5/x )
x = 5/(y-3)
y x - 3 x = 5
y x = 3 x + 5
y = 3 + (5/x )