Find the indefinite integral in two ways.

Question

∫(2x-1)^2 dx

The first way I used was using the power rule and chain rule with substitution.

Let u = 2x - 1
du = 2 dx

(1/2)∫ u^2 du

(Applying power rule)
(1/2) * (u^3/3) + C

=(2x-1)^3/6 + C

What would be another way of finding the indefinite integral??

Answer 1

Just expand the polynomial and integrate all the terms:

4x^2-4x+1 dx