Asked by Butho
good day please help with this indefinite integral,especially what formula i can use to solve it-2x+1/(3x^2+3x+5)dx.Find the indefinite integral.
Answers
Answered by
Steve
since there's a quadratic in the bottom, and a linear factor in the top, it's a good bet you can massage it into something like du/u.
In fact, if we let
u = 3x^2+3x+5
du = 6x+3 = 3(2x+1)
and you have
∫ 1/3 du/u = 1/3 log u + C
= 1/3 log(3x^2+3x+5) + C
In fact, if we let
u = 3x^2+3x+5
du = 6x+3 = 3(2x+1)
and you have
∫ 1/3 du/u = 1/3 log u + C
= 1/3 log(3x^2+3x+5) + C
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