find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=-6+(n-1)(1/5)

Answer 1

To find the first term of the sequence, we simply plug in n=1:

A(1) = -6 + (1-1)(1/5)
A(1) = -6 + 0
A(1) = -6

Therefore, the first term of the sequence is -6.

To find the fourth term of the sequence, we plug in n=4:

A(4) = -6 + (4-1)(1/5)
A(4) = -6 + 3(1/5)
A(4) = -6 + 3/5
A(4) = -6 + 0.6
A(4) = -5.4

Therefore, the fourth term of the sequence is -5.4.

To find the tenth term of the sequence, we plug in n=10:

A(10) = -6 + (10-1)(1/5)
A(10) = -6 + 9(1/5)
A(10) = -6 + 1.8
A(10) = -4.2

Therefore, the tenth term of the sequence is -4.2.