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Find the equation of the tangent line to the curve y=1+ xe^(2x)

y'=(e^(2x))(2x+1) = slope

What's the next step?

2 answers

at the point where x=0 *
substitute 0 in for the slope equation to get slope at x=0, then substitute 0 in for the original equation to get a point (0,y). Then use point slope equation y-y1=m(x-x1). m is the slope and x1,y1 is the point from substituting 0 into the original equation.
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