Find the derivative of xsecy+y^5=5x^3-7

1 answer

x secy + y^5 = 5x^3 - 7
secy + x secy tany y' + 5y^4 y' = 15x^2
(x secy tany + 5y^4)y' = 15x^2 - secy

So,

y' =

15x^2 - secy
----------------------------
x secy tany + 5y^4
Similar Questions
  1. 1.) Find the derivative of tan (sec x).2.) Find the derivative if 1/x in four ways, using the limit process, power rule,
    1. answers icon 1 answer
  2. 1. Find y'(x) whenxsecy - 3y sinx = 1 a) (3ycosx - sec y) / (xsec^2y - 3sinx) b) (3cosx - sec x) / (xsecytany - 3sinx) c)
    1. answers icon 1 answer
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions