It seems the post didn't post so I put it again.
2) use the chain rule where 2 separated parts.
y= (3x+ 5)^8
x= 3x+5
dx= 3
y'= x^8dx
8x^7 dx
put back what x is and get
8*3(3x+5)^7
I just put back the dx as well and moved it to multiply it with the 8
so..
24(3x+5)^7
this is what it should be if I remember how to do this since I'm not looking at my cal book right now
Any help would be much appreciated with the steps involved in each problem given. Thank you.
1) Find derivative if y =cot x + sin x
2) Find derivative if y = (3x+5)^8
3) Find derivative if y = x csc x
4) Find derivative if y = x �ã3x + 1 (3x + 1 is under the square root)
5) ( f ◦ g )�Œ if f ( x) = x^5 + 1 and g (x) = �ãx at x = 1 (the x is under the square root)
Best Regards
1 answer
1 answer